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Question

In the figure below, ∠DEC+∠BFC\angle DEC + \angle BFC is equal to ______. Screenshot 2025-02-02 103711.png

MCQ

∠BCD−∠BAD\angle BCD - \angle BAD

∠BAD+∠BCF\angle BAD + \angle BCF

∠BAD+∠BCD\angle BAD + \angle BCD

∠CBA+∠ADC\angle CBA + \angle ADC

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